35x^4-49x^3+21x/7x

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Solution for 35x^4-49x^3+21x/7x equation: 


x in (-oo:+oo)

35*x^4-(49*x^3)+((21*x)/7)*x = 0

35*x^4-49*x^3+((21*x)/7)*x = 0

35*x^4-49*x^3+3*x^2 = 0

x^2*(35*x^2-49*x+3) = 0

35*x^2-49*x+3 = 0

DELTA = (-49)^2-(3*4*35)

DELTA = 1981

DELTA > 0

x = (1981^(1/2)+49)/(2*35) or x = (49-1981^(1/2))/(2*35)

x = (1981^(1/2)+49)/70 or x = (49-1981^(1/2))/70

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { (49-1981^(1/2))/70, (1981^(1/2)+49)/70, 0 }

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